I'm trying to understand Pay-to-Pubkey-Hash transactions. I picked a random P2PKH transaction in a blockchain explorer: ab3f542ad5add941f8ba4282cebab0cca81266a83cab6b98ebb8ae730477a570
As far as I understand 0312437e326ef7bef6ea13209720f308548d2d205a4bf94e73bf8233ea7e6bb769 in the scriptSig is the public key and 3b10b087f293aecbb3af71e26d17f4e0ff4ea5f7 in the scriptPubKey is the OP_HASH160 of the public key of the receiver. So I did the following:
- SHA256(0312437e326ef7bef6ea13209720f308548d2d205a4bf94e73bf8233ea7e6bb769) = 7205ec1e595ce779b4d8b68fd909e00ef97eb0fdb8274951c7f923e2c82a898f
- RIPEMD160(7205ec1e595ce779b4d8b68fd909e00ef97eb0fdb8274951c7f923e2c82a898f) = 73e440177e6b5e27eabef63905bb2e2c1616dc9d
I was expecting the second step to result in 3b10b087f293aecbb3af71e26d17f4e0ff4ea5f7.
What am I doing wrong?
from Recent Questions - Bitcoin Stack Exchange
November 21, 2022 at 03:20AM